pour la 1)a) please

Bonjour,

f(x)=(x/100+1)*√x

f'(x)=1/100*√x+(x/100+1)*1/2*1/√x
=1/(2√x) *(2/100*x+x/100+1)
=(3x/100+1)/(2√x)
=(0.03x+1)/(2√x)