(72) Developper les expressions suursarites 1=(x-2)(x+3) 2= (x+2)(x-1) 3 = 3-(3-(2-2)] - [4 7(2 +22)] 4= 5(32-2) (22-3) - 3(2x++) (2₂+4) 2 5=(x-7) + (3x+2) (= 5
Mathématiques
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Question
(72) Developper les expressions suursarites
1=(x-2)(x+3)
2= (x+2)(x-1)
3 = 3-(3-(2-2)] - [4 7(2 +22)]
4= 5(32-2) (22-3) - 3(2x++) (2₂+4)
2
5=(x-7) + (3x+2)
(= 5(2x-4) (2x+2)
구
x
8 = 5(3x+4)²- 3 (52-2)²
9 = (3x-4)² = (x+4) ²+₂ (2-4)²
= (5x+4)²-(2x-4)²
1=(x-2)(x+3)
2= (x+2)(x-1)
3 = 3-(3-(2-2)] - [4 7(2 +22)]
4= 5(32-2) (22-3) - 3(2x++) (2₂+4)
2
5=(x-7) + (3x+2)
(= 5(2x-4) (2x+2)
구
x
8 = 5(3x+4)²- 3 (52-2)²
9 = (3x-4)² = (x+4) ²+₂ (2-4)²
= (5x+4)²-(2x-4)²