aidez moi a faire CA (6x-4)2 =(x-1)2

(6x-4)² = (x-1)²

(6x-4)²-(x-1)² = 0

(6x-4-x+1)(6x-4+x-1) = 0

(5x-3)(7x-5) = 0

5x-3 = 0
5x = 3
x = 3/5

7x-5 = 0
7x = 5
x = 5/7

il y a deux methodes de de résoudre le problème / l'exercice.

la plus facile methode:

[tex](6x -4)^2 = (x-1)^2\\\\(6x-4)=+(x-1)\ \ ou\ \ \ -(x-1)\\\\1)\ 6x-4 = x-1\\5x=3,\ \ \ x=3/5\\\\2)\ 6x-4=-(x-1)\\7x=5,\ \ x=5/7\\[/tex]

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[tex](6x - 4)^2 = (x-2)^2\\\\36x^2-48x+16 = x^2-2x+1\\35x^2-46 x+15 =0\\35x^2-21x-25x+15=0\\7x(5x-3)-5(5x-3)=0\\(7x-5)(5x-3)=0\\x = 5/7 \ ou\ 3/5\\[/tex]


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